| 1 | /* enough.c -- determine the maximum size of inflate's Huffman code tables over | 
 
 
 
 
 | 2 | * all possible valid and complete Huffman codes, subject to a length limit. | 
 
 
 
 
 | 3 | * Copyright (C) 2007, 2008, 2012 Mark Adler | 
 
 
 
 
 | 4 | * Version 1.4  18 August 2012  Mark Adler | 
 
 
 
 
 | 5 | */ | 
 
 
 
 
 | 6 |  | 
 
 
 
 
 | 7 | /* Version history: | 
 
 
 
 
 | 8 | 1.0   3 Jan 2007  First version (derived from codecount.c version 1.4) | 
 
 
 
 
 | 9 | 1.1   4 Jan 2007  Use faster incremental table usage computation | 
 
 
 
 
 | 10 | Prune examine() search on previously visited states | 
 
 
 
 
 | 11 | 1.2   5 Jan 2007  Comments clean up | 
 
 
 
 
 | 12 | As inflate does, decrease root for short codes | 
 
 
 
 
 | 13 | Refuse cases where inflate would increase root | 
 
 
 
 
 | 14 | 1.3  17 Feb 2008  Add argument for initial root table size | 
 
 
 
 
 | 15 | Fix bug for initial root table size == max - 1 | 
 
 
 
 
 | 16 | Use a macro to compute the history index | 
 
 
 
 
 | 17 | 1.4  18 Aug 2012  Avoid shifts more than bits in type (caused endless loop!) | 
 
 
 
 
 | 18 | Clean up comparisons of different types | 
 
 
 
 
 | 19 | Clean up code indentation | 
 
 
 
 
 | 20 | */ | 
 
 
 
 
 | 21 |  | 
 
 
 
 
 | 22 | /* | 
 
 
 
 
 | 23 | Examine all possible Huffman codes for a given number of symbols and a | 
 
 
 
 
 | 24 | maximum code length in bits to determine the maximum table size for zilb's | 
 
 
 
 
 | 25 | inflate.  Only complete Huffman codes are counted. | 
 
 
 
 
 | 26 |  | 
 
 
 
 
 | 27 | Two codes are considered distinct if the vectors of the number of codes per | 
 
 
 
 
 | 28 | length are not identical.  So permutations of the symbol assignments result | 
 
 
 
 
 | 29 | in the same code for the counting, as do permutations of the assignments of | 
 
 
 
 
 | 30 | the bit values to the codes (i.e. only canonical codes are counted). | 
 
 
 
 
 | 31 |  | 
 
 
 
 
 | 32 | We build a code from shorter to longer lengths, determining how many symbols | 
 
 
 
 
 | 33 | are coded at each length.  At each step, we have how many symbols remain to | 
 
 
 
 
 | 34 | be coded, what the last code length used was, and how many bit patterns of | 
 
 
 
 
 | 35 | that length remain unused. Then we add one to the code length and double the | 
 
 
 
 
 | 36 | number of unused patterns to graduate to the next code length.  We then | 
 
 
 
 
 | 37 | assign all portions of the remaining symbols to that code length that | 
 
 
 
 
 | 38 | preserve the properties of a correct and eventually complete code.  Those | 
 
 
 
 
 | 39 | properties are: we cannot use more bit patterns than are available; and when | 
 
 
 
 
 | 40 | all the symbols are used, there are exactly zero possible bit patterns | 
 
 
 
 
 | 41 | remaining. | 
 
 
 
 
 | 42 |  | 
 
 
 
 
 | 43 | The inflate Huffman decoding algorithm uses two-level lookup tables for | 
 
 
 
 
 | 44 | speed.  There is a single first-level table to decode codes up to root bits | 
 
 
 
 
 | 45 | in length (root == 9 in the current inflate implementation).  The table | 
 
 
 
 
 | 46 | has 1 << root entries and is indexed by the next root bits of input.  Codes | 
 
 
 
 
 | 47 | shorter than root bits have replicated table entries, so that the correct | 
 
 
 
 
 | 48 | entry is pointed to regardless of the bits that follow the short code.  If | 
 
 
 
 
 | 49 | the code is longer than root bits, then the table entry points to a second- | 
 
 
 
 
 | 50 | level table.  The size of that table is determined by the longest code with | 
 
 
 
 
 | 51 | that root-bit prefix.  If that longest code has length len, then the table | 
 
 
 
 
 | 52 | has size 1 << (len - root), to index the remaining bits in that set of | 
 
 
 
 
 | 53 | codes.  Each subsequent root-bit prefix then has its own sub-table.  The | 
 
 
 
 
 | 54 | total number of table entries required by the code is calculated | 
 
 
 
 
 | 55 | incrementally as the number of codes at each bit length is populated.  When | 
 
 
 
 
 | 56 | all of the codes are shorter than root bits, then root is reduced to the | 
 
 
 
 
 | 57 | longest code length, resulting in a single, smaller, one-level table. | 
 
 
 
 
 | 58 |  | 
 
 
 
 
 | 59 | The inflate algorithm also provides for small values of root (relative to | 
 
 
 
 
 | 60 | the log2 of the number of symbols), where the shortest code has more bits | 
 
 
 
 
 | 61 | than root.  In that case, root is increased to the length of the shortest | 
 
 
 
 
 | 62 | code.  This program, by design, does not handle that case, so it is verified | 
 
 
 
 
 | 63 | that the number of symbols is less than 2^(root + 1). | 
 
 
 
 
 | 64 |  | 
 
 
 
 
 | 65 | In order to speed up the examination (by about ten orders of magnitude for | 
 
 
 
 
 | 66 | the default arguments), the intermediate states in the build-up of a code | 
 
 
 
 
 | 67 | are remembered and previously visited branches are pruned.  The memory | 
 
 
 
 
 | 68 | required for this will increase rapidly with the total number of symbols and | 
 
 
 
 
 | 69 | the maximum code length in bits.  However this is a very small price to pay | 
 
 
 
 
 | 70 | for the vast speedup. | 
 
 
 
 
 | 71 |  | 
 
 
 
 
 | 72 | First, all of the possible Huffman codes are counted, and reachable | 
 
 
 
 
 | 73 | intermediate states are noted by a non-zero count in a saved-results array. | 
 
 
 
 
 | 74 | Second, the intermediate states that lead to (root + 1) bit or longer codes | 
 
 
 
 
 | 75 | are used to look at all sub-codes from those junctures for their inflate | 
 
 
 
 
 | 76 | memory usage.  (The amount of memory used is not affected by the number of | 
 
 
 
 
 | 77 | codes of root bits or less in length.)  Third, the visited states in the | 
 
 
 
 
 | 78 | construction of those sub-codes and the associated calculation of the table | 
 
 
 
 
 | 79 | size is recalled in order to avoid recalculating from the same juncture. | 
 
 
 
 
 | 80 | Beginning the code examination at (root + 1) bit codes, which is enabled by | 
 
 
 
 
 | 81 | identifying the reachable nodes, accounts for about six of the orders of | 
 
 
 
 
 | 82 | magnitude of improvement for the default arguments.  About another four | 
 
 
 
 
 | 83 | orders of magnitude come from not revisiting previous states.  Out of | 
 
 
 
 
 | 84 | approximately 2x10^16 possible Huffman codes, only about 2x10^6 sub-codes | 
 
 
 
 
 | 85 | need to be examined to cover all of the possible table memory usage cases | 
 
 
 
 
 | 86 | for the default arguments of 286 symbols limited to 15-bit codes. | 
 
 
 
 
 | 87 |  | 
 
 
 
 
 | 88 | Note that an unsigned long long type is used for counting.  It is quite easy | 
 
 
 
 
 | 89 | to exceed the capacity of an eight-byte integer with a large number of | 
 
 
 
 
 | 90 | symbols and a large maximum code length, so multiple-precision arithmetic | 
 
 
 
 
 | 91 | would need to replace the unsigned long long arithmetic in that case.  This | 
 
 
 
 
 | 92 | program will abort if an overflow occurs.  The big_t type identifies where | 
 
 
 
 
 | 93 | the counting takes place. | 
 
 
 
 
 | 94 |  | 
 
 
 
 
 | 95 | An unsigned long long type is also used for calculating the number of | 
 
 
 
 
 | 96 | possible codes remaining at the maximum length.  This limits the maximum | 
 
 
 
 
 | 97 | code length to the number of bits in a long long minus the number of bits | 
 
 
 
 
 | 98 | needed to represent the symbols in a flat code.  The code_t type identifies | 
 
 
 
 
 | 99 | where the bit pattern counting takes place. | 
 
 
 
 
 | 100 | */ | 
 
 
 
 
 | 101 |  | 
 
 
 
 
 | 102 | #include <stdio.h> | 
 
 
 
 
 | 103 | #include <stdlib.h> | 
 
 
 
 
 | 104 | #include <string.h> | 
 
 
 
 
 | 105 | #include <assert.h> | 
 
 
 
 
 | 106 |  | 
 
 
 
 
 | 107 | #define local static | 
 
 
 
 
 | 108 |  | 
 
 
 
 
 | 109 | /* special data types */ | 
 
 
 
 
 | 110 | typedef unsigned long long big_t;   /* type for code counting */ | 
 
 
 
 
 | 111 | typedef unsigned long long code_t;  /* type for bit pattern counting */ | 
 
 
 
 
 | 112 | struct tab {                        /* type for been here check */ | 
 
 
 
 
 | 113 | size_t len;         /* length of bit vector in char's */ | 
 
 
 
 
 | 114 | char *vec;          /* allocated bit vector */ | 
 
 
 
 
 | 115 | }; | 
 
 
 
 
 | 116 |  | 
 
 
 
 
 | 117 | /* The array for saving results, num[], is indexed with this triplet: | 
 
 
 
 
 | 118 |  | 
 
 
 
 
 | 119 | syms: number of symbols remaining to code | 
 
 
 
 
 | 120 | left: number of available bit patterns at length len | 
 
 
 
 
 | 121 | len: number of bits in the codes currently being assigned | 
 
 
 
 
 | 122 |  | 
 
 
 
 
 | 123 | Those indices are constrained thusly when saving results: | 
 
 
 
 
 | 124 |  | 
 
 
 
 
 | 125 | syms: 3..totsym (totsym == total symbols to code) | 
 
 
 
 
 | 126 | left: 2..syms - 1, but only the evens (so syms == 8 -> 2, 4, 6) | 
 
 
 
 
 | 127 | len: 1..max - 1 (max == maximum code length in bits) | 
 
 
 
 
 | 128 |  | 
 
 
 
 
 | 129 | syms == 2 is not saved since that immediately leads to a single code.  left | 
 
 
 
 
 | 130 | must be even, since it represents the number of available bit patterns at | 
 
 
 
 
 | 131 | the current length, which is double the number at the previous length. | 
 
 
 
 
 | 132 | left ends at syms-1 since left == syms immediately results in a single code. | 
 
 
 
 
 | 133 | (left > sym is not allowed since that would result in an incomplete code.) | 
 
 
 
 
 | 134 | len is less than max, since the code completes immediately when len == max. | 
 
 
 
 
 | 135 |  | 
 
 
 
 
 | 136 | The offset into the array is calculated for the three indices with the | 
 
 
 
 
 | 137 | first one (syms) being outermost, and the last one (len) being innermost. | 
 
 
 
 
 | 138 | We build the array with length max-1 lists for the len index, with syms-3 | 
 
 
 
 
 | 139 | of those for each symbol.  There are totsym-2 of those, with each one | 
 
 
 
 
 | 140 | varying in length as a function of sym.  See the calculation of index in | 
 
 
 
 
 | 141 | count() for the index, and the calculation of size in main() for the size | 
 
 
 
 
 | 142 | of the array. | 
 
 
 
 
 | 143 |  | 
 
 
 
 
 | 144 | For the deflate example of 286 symbols limited to 15-bit codes, the array | 
 
 
 
 
 | 145 | has 284,284 entries, taking up 2.17 MB for an 8-byte big_t.  More than | 
 
 
 
 
 | 146 | half of the space allocated for saved results is actually used -- not all | 
 
 
 
 
 | 147 | possible triplets are reached in the generation of valid Huffman codes. | 
 
 
 
 
 | 148 | */ | 
 
 
 
 
 | 149 |  | 
 
 
 
 
 | 150 | /* The array for tracking visited states, done[], is itself indexed identically | 
 
 
 
 
 | 151 | to the num[] array as described above for the (syms, left, len) triplet. | 
 
 
 
 
 | 152 | Each element in the array is further indexed by the (mem, rem) doublet, | 
 
 
 
 
 | 153 | where mem is the amount of inflate table space used so far, and rem is the | 
 
 
 
 
 | 154 | remaining unused entries in the current inflate sub-table.  Each indexed | 
 
 
 
 
 | 155 | element is simply one bit indicating whether the state has been visited or | 
 
 
 
 
 | 156 | not.  Since the ranges for mem and rem are not known a priori, each bit | 
 
 
 
 
 | 157 | vector is of a variable size, and grows as needed to accommodate the visited | 
 
 
 
 
 | 158 | states.  mem and rem are used to calculate a single index in a triangular | 
 
 
 
 
 | 159 | array.  Since the range of mem is expected in the default case to be about | 
 
 
 
 
 | 160 | ten times larger than the range of rem, the array is skewed to reduce the | 
 
 
 
 
 | 161 | memory usage, with eight times the range for mem than for rem.  See the | 
 
 
 
 
 | 162 | calculations for offset and bit in beenhere() for the details. | 
 
 
 
 
 | 163 |  | 
 
 
 
 
 | 164 | For the deflate example of 286 symbols limited to 15-bit codes, the bit | 
 
 
 
 
 | 165 | vectors grow to total approximately 21 MB, in addition to the 4.3 MB done[] | 
 
 
 
 
 | 166 | array itself. | 
 
 
 
 
 | 167 | */ | 
 
 
 
 
 | 168 |  | 
 
 
 
 
 | 169 | /* Globals to avoid propagating constants or constant pointers recursively */ | 
 
 
 
 
 | 170 | local int max;          /* maximum allowed bit length for the codes */ | 
 
 
 
 
 | 171 | local int root;         /* size of base code table in bits */ | 
 
 
 
 
 | 172 | local int large;        /* largest code table so far */ | 
 
 
 
 
 | 173 | local size_t size;      /* number of elements in num and done */ | 
 
 
 
 
 | 174 | local int *code;        /* number of symbols assigned to each bit length */ | 
 
 
 
 
 | 175 | local big_t *num;       /* saved results array for code counting */ | 
 
 
 
 
 | 176 | local struct tab *done; /* states already evaluated array */ | 
 
 
 
 
 | 177 |  | 
 
 
 
 
 | 178 | /* Index function for num[] and done[] */ | 
 
 
 
 
 | 179 | #define INDEX(i,j,k) (((size_t)((i-1)>>1)*((i-2)>>1)+(j>>1)-1)*(max-1)+k-1) | 
 
 
 
 
 | 180 |  | 
 
 
 
 
 | 181 | /* Free allocated space.  Uses globals code, num, and done. */ | 
 
 
 
 
 | 182 | local void cleanup(void) | 
 
 
 
 
 | 183 | { | 
 
 
 
 
 | 184 | size_t n; | 
 
 
 
 
 | 185 |  | 
 
 
 
 
 | 186 | if (done != NULL) { | 
 
 
 
 
 | 187 | for (n = 0; n < size; n++) | 
 
 
 
 
 | 188 | if (done[n].len) | 
 
 
 
 
 | 189 | free(done[n].vec); | 
 
 
 
 
 | 190 | free(done); | 
 
 
 
 
 | 191 | } | 
 
 
 
 
 | 192 | if (num != NULL) | 
 
 
 
 
 | 193 | free(num); | 
 
 
 
 
 | 194 | if (code != NULL) | 
 
 
 
 
 | 195 | free(code); | 
 
 
 
 
 | 196 | } | 
 
 
 
 
 | 197 |  | 
 
 
 
 
 | 198 | /* Return the number of possible Huffman codes using bit patterns of lengths | 
 
 
 
 
 | 199 | len through max inclusive, coding syms symbols, with left bit patterns of | 
 
 
 
 
 | 200 | length len unused -- return -1 if there is an overflow in the counting. | 
 
 
 
 
 | 201 | Keep a record of previous results in num to prevent repeating the same | 
 
 
 
 
 | 202 | calculation.  Uses the globals max and num. */ | 
 
 
 
 
 | 203 | local big_t count(int syms, int len, int left) | 
 
 
 
 
 | 204 | { | 
 
 
 
 
 | 205 | big_t sum;          /* number of possible codes from this juncture */ | 
 
 
 
 
 | 206 | big_t got;          /* value returned from count() */ | 
 
 
 
 
 | 207 | int least;          /* least number of syms to use at this juncture */ | 
 
 
 
 
 | 208 | int most;           /* most number of syms to use at this juncture */ | 
 
 
 
 
 | 209 | int use;            /* number of bit patterns to use in next call */ | 
 
 
 
 
 | 210 | size_t index;       /* index of this case in *num */ | 
 
 
 
 
 | 211 |  | 
 
 
 
 
 | 212 | /* see if only one possible code */ | 
 
 
 
 
 | 213 | if (syms == left) | 
 
 
 
 
 | 214 | return 1; | 
 
 
 
 
 | 215 |  | 
 
 
 
 
 | 216 | /* note and verify the expected state */ | 
 
 
 
 
 | 217 | assert(syms > left && left > 0 && len < max); | 
 
 
 
 
 | 218 |  | 
 
 
 
 
 | 219 | /* see if we've done this one already */ | 
 
 
 
 
 | 220 | index = INDEX(syms, left, len); | 
 
 
 
 
 | 221 | got = num[index]; | 
 
 
 
 
 | 222 | if (got) | 
 
 
 
 
 | 223 | return got;         /* we have -- return the saved result */ | 
 
 
 
 
 | 224 |  | 
 
 
 
 
 | 225 | /* we need to use at least this many bit patterns so that the code won't be | 
 
 
 
 
 | 226 | incomplete at the next length (more bit patterns than symbols) */ | 
 
 
 
 
 | 227 | least = (left << 1) - syms; | 
 
 
 
 
 | 228 | if (least < 0) | 
 
 
 
 
 | 229 | least = 0; | 
 
 
 
 
 | 230 |  | 
 
 
 
 
 | 231 | /* we can use at most this many bit patterns, lest there not be enough | 
 
 
 
 
 | 232 | available for the remaining symbols at the maximum length (if there were | 
 
 
 
 
 | 233 | no limit to the code length, this would become: most = left - 1) */ | 
 
 
 
 
 | 234 | most = (((code_t)left << (max - len)) - syms) / | 
 
 
 
 
 | 235 | (((code_t)1 << (max - len)) - 1); | 
 
 
 
 
 | 236 |  | 
 
 
 
 
 | 237 | /* count all possible codes from this juncture and add them up */ | 
 
 
 
 
 | 238 | sum = 0; | 
 
 
 
 
 | 239 | for (use = least; use <= most; use++) { | 
 
 
 
 
 | 240 | got = count(syms - use, len + 1, (left - use) << 1); | 
 
 
 
 
 | 241 | sum += got; | 
 
 
 
 
 | 242 | if (got == (big_t)0 - 1 || sum < got)   /* overflow */ | 
 
 
 
 
 | 243 | return (big_t)0 - 1; | 
 
 
 
 
 | 244 | } | 
 
 
 
 
 | 245 |  | 
 
 
 
 
 | 246 | /* verify that all recursive calls are productive */ | 
 
 
 
 
 | 247 | assert(sum != 0); | 
 
 
 
 
 | 248 |  | 
 
 
 
 
 | 249 | /* save the result and return it */ | 
 
 
 
 
 | 250 | num[index] = sum; | 
 
 
 
 
 | 251 | return sum; | 
 
 
 
 
 | 252 | } | 
 
 
 
 
 | 253 |  | 
 
 
 
 
 | 254 | /* Return true if we've been here before, set to true if not.  Set a bit in a | 
 
 
 
 
 | 255 | bit vector to indicate visiting this state.  Each (syms,len,left) state | 
 
 
 
 
 | 256 | has a variable size bit vector indexed by (mem,rem).  The bit vector is | 
 
 
 
 
 | 257 | lengthened if needed to allow setting the (mem,rem) bit. */ | 
 
 
 
 
 | 258 | local int beenhere(int syms, int len, int left, int mem, int rem) | 
 
 
 
 
 | 259 | { | 
 
 
 
 
 | 260 | size_t index;       /* index for this state's bit vector */ | 
 
 
 
 
 | 261 | size_t offset;      /* offset in this state's bit vector */ | 
 
 
 
 
 | 262 | int bit;            /* mask for this state's bit */ | 
 
 
 
 
 | 263 | size_t length;      /* length of the bit vector in bytes */ | 
 
 
 
 
 | 264 | char *vector;       /* new or enlarged bit vector */ | 
 
 
 
 
 | 265 |  | 
 
 
 
 
 | 266 | /* point to vector for (syms,left,len), bit in vector for (mem,rem) */ | 
 
 
 
 
 | 267 | index = INDEX(syms, left, len); | 
 
 
 
 
 | 268 | mem -= 1 << root; | 
 
 
 
 
 | 269 | offset = (mem >> 3) + rem; | 
 
 
 
 
 | 270 | offset = ((offset * (offset + 1)) >> 1) + rem; | 
 
 
 
 
 | 271 | bit = 1 << (mem & 7); | 
 
 
 
 
 | 272 |  | 
 
 
 
 
 | 273 | /* see if we've been here */ | 
 
 
 
 
 | 274 | length = done[index].len; | 
 
 
 
 
 | 275 | if (offset < length && (done[index].vec[offset] & bit) != 0) | 
 
 
 
 
 | 276 | return 1;       /* done this! */ | 
 
 
 
 
 | 277 |  | 
 
 
 
 
 | 278 | /* we haven't been here before -- set the bit to show we have now */ | 
 
 
 
 
 | 279 |  | 
 
 
 
 
 | 280 | /* see if we need to lengthen the vector in order to set the bit */ | 
 
 
 
 
 | 281 | if (length <= offset) { | 
 
 
 
 
 | 282 | /* if we have one already, enlarge it, zero out the appended space */ | 
 
 
 
 
 | 283 | if (length) { | 
 
 
 
 
 | 284 | do { | 
 
 
 
 
 | 285 | length <<= 1; | 
 
 
 
 
 | 286 | } while (length <= offset); | 
 
 
 
 
 | 287 | vector = realloc(done[index].vec, length); | 
 
 
 
 
 | 288 | if (vector != NULL) | 
 
 
 
 
 | 289 | memset(vector + done[index].len, 0, length - done[index].len); | 
 
 
 
 
 | 290 | } | 
 
 
 
 
 | 291 |  | 
 
 
 
 
 | 292 | /* otherwise we need to make a new vector and zero it out */ | 
 
 
 
 
 | 293 | else { | 
 
 
 
 
 | 294 | length = 1 << (len - root); | 
 
 
 
 
 | 295 | while (length <= offset) | 
 
 
 
 
 | 296 | length <<= 1; | 
 
 
 
 
 | 297 | vector = calloc(length, sizeof(char)); | 
 
 
 
 
 | 298 | } | 
 
 
 
 
 | 299 |  | 
 
 
 
 
 | 300 | /* in either case, bail if we can't get the memory */ | 
 
 
 
 
 | 301 | if (vector == NULL) { | 
 
 
 
 
 | 302 | fputs("abort: unable to allocate enough memory\n", stderr); | 
 
 
 
 
 | 303 | cleanup(); | 
 
 
 
 
 | 304 | exit(1); | 
 
 
 
 
 | 305 | } | 
 
 
 
 
 | 306 |  | 
 
 
 
 
 | 307 | /* install the new vector */ | 
 
 
 
 
 | 308 | done[index].len = length; | 
 
 
 
 
 | 309 | done[index].vec = vector; | 
 
 
 
 
 | 310 | } | 
 
 
 
 
 | 311 |  | 
 
 
 
 
 | 312 | /* set the bit */ | 
 
 
 
 
 | 313 | done[index].vec[offset] |= bit; | 
 
 
 
 
 | 314 | return 0; | 
 
 
 
 
 | 315 | } | 
 
 
 
 
 | 316 |  | 
 
 
 
 
 | 317 | /* Examine all possible codes from the given node (syms, len, left).  Compute | 
 
 
 
 
 | 318 | the amount of memory required to build inflate's decoding tables, where the | 
 
 
 
 
 | 319 | number of code structures used so far is mem, and the number remaining in | 
 
 
 
 
 | 320 | the current sub-table is rem.  Uses the globals max, code, root, large, and | 
 
 
 
 
 | 321 | done. */ | 
 
 
 
 
 | 322 | local void examine(int syms, int len, int left, int mem, int rem) | 
 
 
 
 
 | 323 | { | 
 
 
 
 
 | 324 | int least;          /* least number of syms to use at this juncture */ | 
 
 
 
 
 | 325 | int most;           /* most number of syms to use at this juncture */ | 
 
 
 
 
 | 326 | int use;            /* number of bit patterns to use in next call */ | 
 
 
 
 
 | 327 |  | 
 
 
 
 
 | 328 | /* see if we have a complete code */ | 
 
 
 
 
 | 329 | if (syms == left) { | 
 
 
 
 
 | 330 | /* set the last code entry */ | 
 
 
 
 
 | 331 | code[len] = left; | 
 
 
 
 
 | 332 |  | 
 
 
 
 
 | 333 | /* complete computation of memory used by this code */ | 
 
 
 
 
 | 334 | while (rem < left) { | 
 
 
 
 
 | 335 | left -= rem; | 
 
 
 
 
 | 336 | rem = 1 << (len - root); | 
 
 
 
 
 | 337 | mem += rem; | 
 
 
 
 
 | 338 | } | 
 
 
 
 
 | 339 | assert(rem == left); | 
 
 
 
 
 | 340 |  | 
 
 
 
 
 | 341 | /* if this is a new maximum, show the entries used and the sub-code */ | 
 
 
 
 
 | 342 | if (mem > large) { | 
 
 
 
 
 | 343 | large = mem; | 
 
 
 
 
 | 344 | printf("max %d: ", mem); | 
 
 
 
 
 | 345 | for (use = root + 1; use <= max; use++) | 
 
 
 
 
 | 346 | if (code[use]) | 
 
 
 
 
 | 347 | printf("%d[%d] ", code[use], use); | 
 
 
 
 
 | 348 | putchar('\n'); | 
 
 
 
 
 | 349 | fflush(stdout); | 
 
 
 
 
 | 350 | } | 
 
 
 
 
 | 351 |  | 
 
 
 
 
 | 352 | /* remove entries as we drop back down in the recursion */ | 
 
 
 
 
 | 353 | code[len] = 0; | 
 
 
 
 
 | 354 | return; | 
 
 
 
 
 | 355 | } | 
 
 
 
 
 | 356 |  | 
 
 
 
 
 | 357 | /* prune the tree if we can */ | 
 
 
 
 
 | 358 | if (beenhere(syms, len, left, mem, rem)) | 
 
 
 
 
 | 359 | return; | 
 
 
 
 
 | 360 |  | 
 
 
 
 
 | 361 | /* we need to use at least this many bit patterns so that the code won't be | 
 
 
 
 
 | 362 | incomplete at the next length (more bit patterns than symbols) */ | 
 
 
 
 
 | 363 | least = (left << 1) - syms; | 
 
 
 
 
 | 364 | if (least < 0) | 
 
 
 
 
 | 365 | least = 0; | 
 
 
 
 
 | 366 |  | 
 
 
 
 
 | 367 | /* we can use at most this many bit patterns, lest there not be enough | 
 
 
 
 
 | 368 | available for the remaining symbols at the maximum length (if there were | 
 
 
 
 
 | 369 | no limit to the code length, this would become: most = left - 1) */ | 
 
 
 
 
 | 370 | most = (((code_t)left << (max - len)) - syms) / | 
 
 
 
 
 | 371 | (((code_t)1 << (max - len)) - 1); | 
 
 
 
 
 | 372 |  | 
 
 
 
 
 | 373 | /* occupy least table spaces, creating new sub-tables as needed */ | 
 
 
 
 
 | 374 | use = least; | 
 
 
 
 
 | 375 | while (rem < use) { | 
 
 
 
 
 | 376 | use -= rem; | 
 
 
 
 
 | 377 | rem = 1 << (len - root); | 
 
 
 
 
 | 378 | mem += rem; | 
 
 
 
 
 | 379 | } | 
 
 
 
 
 | 380 | rem -= use; | 
 
 
 
 
 | 381 |  | 
 
 
 
 
 | 382 | /* examine codes from here, updating table space as we go */ | 
 
 
 
 
 | 383 | for (use = least; use <= most; use++) { | 
 
 
 
 
 | 384 | code[len] = use; | 
 
 
 
 
 | 385 | examine(syms - use, len + 1, (left - use) << 1, | 
 
 
 
 
 | 386 | mem + (rem ? 1 << (len - root) : 0), rem << 1); | 
 
 
 
 
 | 387 | if (rem == 0) { | 
 
 
 
 
 | 388 | rem = 1 << (len - root); | 
 
 
 
 
 | 389 | mem += rem; | 
 
 
 
 
 | 390 | } | 
 
 
 
 
 | 391 | rem--; | 
 
 
 
 
 | 392 | } | 
 
 
 
 
 | 393 |  | 
 
 
 
 
 | 394 | /* remove entries as we drop back down in the recursion */ | 
 
 
 
 
 | 395 | code[len] = 0; | 
 
 
 
 
 | 396 | } | 
 
 
 
 
 | 397 |  | 
 
 
 
 
 | 398 | /* Look at all sub-codes starting with root + 1 bits.  Look at only the valid | 
 
 
 
 
 | 399 | intermediate code states (syms, left, len).  For each completed code, | 
 
 
 
 
 | 400 | calculate the amount of memory required by inflate to build the decoding | 
 
 
 
 
 | 401 | tables. Find the maximum amount of memory required and show the code that | 
 
 
 
 
 | 402 | requires that maximum.  Uses the globals max, root, and num. */ | 
 
 
 
 
 | 403 | local void enough(int syms) | 
 
 
 
 
 | 404 | { | 
 
 
 
 
 | 405 | int n;              /* number of remaing symbols for this node */ | 
 
 
 
 
 | 406 | int left;           /* number of unused bit patterns at this length */ | 
 
 
 
 
 | 407 | size_t index;       /* index of this case in *num */ | 
 
 
 
 
 | 408 |  | 
 
 
 
 
 | 409 | /* clear code */ | 
 
 
 
 
 | 410 | for (n = 0; n <= max; n++) | 
 
 
 
 
 | 411 | code[n] = 0; | 
 
 
 
 
 | 412 |  | 
 
 
 
 
 | 413 | /* look at all (root + 1) bit and longer codes */ | 
 
 
 
 
 | 414 | large = 1 << root;              /* base table */ | 
 
 
 
 
 | 415 | if (root < max)                 /* otherwise, there's only a base table */ | 
 
 
 
 
 | 416 | for (n = 3; n <= syms; n++) | 
 
 
 
 
 | 417 | for (left = 2; left < n; left += 2) | 
 
 
 
 
 | 418 | { | 
 
 
 
 
 | 419 | /* look at all reachable (root + 1) bit nodes, and the | 
 
 
 
 
 | 420 | resulting codes (complete at root + 2 or more) */ | 
 
 
 
 
 | 421 | index = INDEX(n, left, root + 1); | 
 
 
 
 
 | 422 | if (root + 1 < max && num[index])       /* reachable node */ | 
 
 
 
 
 | 423 | examine(n, root + 1, left, 1 << root, 0); | 
 
 
 
 
 | 424 |  | 
 
 
 
 
 | 425 | /* also look at root bit codes with completions at root + 1 | 
 
 
 
 
 | 426 | bits (not saved in num, since complete), just in case */ | 
 
 
 
 
 | 427 | if (num[index - 1] && n <= left << 1) | 
 
 
 
 
 | 428 | examine((n - left) << 1, root + 1, (n - left) << 1, | 
 
 
 
 
 | 429 | 1 << root, 0); | 
 
 
 
 
 | 430 | } | 
 
 
 
 
 | 431 |  | 
 
 
 
 
 | 432 | /* done */ | 
 
 
 
 
 | 433 | printf("done: maximum of %d table entries\n", large); | 
 
 
 
 
 | 434 | } | 
 
 
 
 
 | 435 |  | 
 
 
 
 
 | 436 | /* | 
 
 
 
 
 | 437 | Examine and show the total number of possible Huffman codes for a given | 
 
 
 
 
 | 438 | maximum number of symbols, initial root table size, and maximum code length | 
 
 
 
 
 | 439 | in bits -- those are the command arguments in that order.  The default | 
 
 
 
 
 | 440 | values are 286, 9, and 15 respectively, for the deflate literal/length code. | 
 
 
 
 
 | 441 | The possible codes are counted for each number of coded symbols from two to | 
 
 
 
 
 | 442 | the maximum.  The counts for each of those and the total number of codes are | 
 
 
 
 
 | 443 | shown.  The maximum number of inflate table entires is then calculated | 
 
 
 
 
 | 444 | across all possible codes.  Each new maximum number of table entries and the | 
 
 
 
 
 | 445 | associated sub-code (starting at root + 1 == 10 bits) is shown. | 
 
 
 
 
 | 446 |  | 
 
 
 
 
 | 447 | To count and examine Huffman codes that are not length-limited, provide a | 
 
 
 
 
 | 448 | maximum length equal to the number of symbols minus one. | 
 
 
 
 
 | 449 |  | 
 
 
 
 
 | 450 | For the deflate literal/length code, use "enough".  For the deflate distance | 
 
 
 
 
 | 451 | code, use "enough 30 6". | 
 
 
 
 
 | 452 |  | 
 
 
 
 
 | 453 | This uses the %llu printf format to print big_t numbers, which assumes that | 
 
 
 
 
 | 454 | big_t is an unsigned long long.  If the big_t type is changed (for example | 
 
 
 
 
 | 455 | to a multiple precision type), the method of printing will also need to be | 
 
 
 
 
 | 456 | updated. | 
 
 
 
 
 | 457 | */ | 
 
 
 
 
 | 458 | int main(int argc, char **argv) | 
 
 
 
 
 | 459 | { | 
 
 
 
 
 | 460 | int syms;           /* total number of symbols to code */ | 
 
 
 
 
 | 461 | int n;              /* number of symbols to code for this run */ | 
 
 
 
 
 | 462 | big_t got;          /* return value of count() */ | 
 
 
 
 
 | 463 | big_t sum;          /* accumulated number of codes over n */ | 
 
 
 
 
 | 464 | code_t word;        /* for counting bits in code_t */ | 
 
 
 
 
 | 465 |  | 
 
 
 
 
 | 466 | /* set up globals for cleanup() */ | 
 
 
 
 
 | 467 | code = NULL; | 
 
 
 
 
 | 468 | num = NULL; | 
 
 
 
 
 | 469 | done = NULL; | 
 
 
 
 
 | 470 |  | 
 
 
 
 
 | 471 | /* get arguments -- default to the deflate literal/length code */ | 
 
 
 
 
 | 472 | syms = 286; | 
 
 
 
 
 | 473 | root = 9; | 
 
 
 
 
 | 474 | max = 15; | 
 
 
 
 
 | 475 | if (argc > 1) { | 
 
 
 
 
 | 476 | syms = atoi(argv[1]); | 
 
 
 
 
 | 477 | if (argc > 2) { | 
 
 
 
 
 | 478 | root = atoi(argv[2]); | 
 
 
 
 
 | 479 | if (argc > 3) | 
 
 
 
 
 | 480 | max = atoi(argv[3]); | 
 
 
 
 
 | 481 | } | 
 
 
 
 
 | 482 | } | 
 
 
 
 
 | 483 | if (argc > 4 || syms < 2 || root < 1 || max < 1) { | 
 
 
 
 
 | 484 | fputs("invalid arguments, need: [sym >= 2 [root >= 1 [max >= 1]]]\n", | 
 
 
 
 
 | 485 | stderr); | 
 
 
 
 
 | 486 | return 1; | 
 
 
 
 
 | 487 | } | 
 
 
 
 
 | 488 |  | 
 
 
 
 
 | 489 | /* if not restricting the code length, the longest is syms - 1 */ | 
 
 
 
 
 | 490 | if (max > syms - 1) | 
 
 
 
 
 | 491 | max = syms - 1; | 
 
 
 
 
 | 492 |  | 
 
 
 
 
 | 493 | /* determine the number of bits in a code_t */ | 
 
 
 
 
 | 494 | for (n = 0, word = 1; word; n++, word <<= 1) | 
 
 
 
 
 | 495 | ; | 
 
 
 
 
 | 496 |  | 
 
 
 
 
 | 497 | /* make sure that the calculation of most will not overflow */ | 
 
 
 
 
 | 498 | if (max > n || (code_t)(syms - 2) >= (((code_t)0 - 1) >> (max - 1))) { | 
 
 
 
 
 | 499 | fputs("abort: code length too long for internal types\n", stderr); | 
 
 
 
 
 | 500 | return 1; | 
 
 
 
 
 | 501 | } | 
 
 
 
 
 | 502 |  | 
 
 
 
 
 | 503 | /* reject impossible code requests */ | 
 
 
 
 
 | 504 | if ((code_t)(syms - 1) > ((code_t)1 << max) - 1) { | 
 
 
 
 
 | 505 | fprintf(stderr, "%d symbols cannot be coded in %d bits\n", | 
 
 
 
 
 | 506 | syms, max); | 
 
 
 
 
 | 507 | return 1; | 
 
 
 
 
 | 508 | } | 
 
 
 
 
 | 509 |  | 
 
 
 
 
 | 510 | /* allocate code vector */ | 
 
 
 
 
 | 511 | code = calloc(max + 1, sizeof(int)); | 
 
 
 
 
 | 512 | if (code == NULL) { | 
 
 
 
 
 | 513 | fputs("abort: unable to allocate enough memory\n", stderr); | 
 
 
 
 
 | 514 | return 1; | 
 
 
 
 
 | 515 | } | 
 
 
 
 
 | 516 |  | 
 
 
 
 
 | 517 | /* determine size of saved results array, checking for overflows, | 
 
 
 
 
 | 518 | allocate and clear the array (set all to zero with calloc()) */ | 
 
 
 
 
 | 519 | if (syms == 2)              /* iff max == 1 */ | 
 
 
 
 
 | 520 | num = NULL;             /* won't be saving any results */ | 
 
 
 
 
 | 521 | else { | 
 
 
 
 
 | 522 | size = syms >> 1; | 
 
 
 
 
 | 523 | if (size > ((size_t)0 - 1) / (n = (syms - 1) >> 1) || | 
 
 
 
 
 | 524 | (size *= n, size > ((size_t)0 - 1) / (n = max - 1)) || | 
 
 
 
 
 | 525 | (size *= n, size > ((size_t)0 - 1) / sizeof(big_t)) || | 
 
 
 
 
 | 526 | (num = calloc(size, sizeof(big_t))) == NULL) { | 
 
 
 
 
 | 527 | fputs("abort: unable to allocate enough memory\n", stderr); | 
 
 
 
 
 | 528 | cleanup(); | 
 
 
 
 
 | 529 | return 1; | 
 
 
 
 
 | 530 | } | 
 
 
 
 
 | 531 | } | 
 
 
 
 
 | 532 |  | 
 
 
 
 
 | 533 | /* count possible codes for all numbers of symbols, add up counts */ | 
 
 
 
 
 | 534 | sum = 0; | 
 
 
 
 
 | 535 | for (n = 2; n <= syms; n++) { | 
 
 
 
 
 | 536 | got = count(n, 1, 2); | 
 
 
 
 
 | 537 | sum += got; | 
 
 
 
 
 | 538 | if (got == (big_t)0 - 1 || sum < got) {     /* overflow */ | 
 
 
 
 
 | 539 | fputs("abort: can't count that high!\n", stderr); | 
 
 
 
 
 | 540 | cleanup(); | 
 
 
 
 
 | 541 | return 1; | 
 
 
 
 
 | 542 | } | 
 
 
 
 
 | 543 | printf("%llu %d-codes\n", got, n); | 
 
 
 
 
 | 544 | } | 
 
 
 
 
 | 545 | printf("%llu total codes for 2 to %d symbols", sum, syms); | 
 
 
 
 
 | 546 | if (max < syms - 1) | 
 
 
 
 
 | 547 | printf(" (%d-bit length limit)\n", max); | 
 
 
 
 
 | 548 | else | 
 
 
 
 
 | 549 | puts(" (no length limit)"); | 
 
 
 
 
 | 550 |  | 
 
 
 
 
 | 551 | /* allocate and clear done array for beenhere() */ | 
 
 
 
 
 | 552 | if (syms == 2) | 
 
 
 
 
 | 553 | done = NULL; | 
 
 
 
 
 | 554 | else if (size > ((size_t)0 - 1) / sizeof(struct tab) || | 
 
 
 
 
 | 555 | (done = calloc(size, sizeof(struct tab))) == NULL) { | 
 
 
 
 
 | 556 | fputs("abort: unable to allocate enough memory\n", stderr); | 
 
 
 
 
 | 557 | cleanup(); | 
 
 
 
 
 | 558 | return 1; | 
 
 
 
 
 | 559 | } | 
 
 
 
 
 | 560 |  | 
 
 
 
 
 | 561 | /* find and show maximum inflate table usage */ | 
 
 
 
 
 | 562 | if (root > max)                 /* reduce root to max length */ | 
 
 
 
 
 | 563 | root = max; | 
 
 
 
 
 | 564 | if ((code_t)syms < ((code_t)1 << (root + 1))) | 
 
 
 
 
 | 565 | enough(syms); | 
 
 
 
 
 | 566 | else | 
 
 
 
 
 | 567 | puts("cannot handle minimum code lengths > root"); | 
 
 
 
 
 | 568 |  | 
 
 
 
 
 | 569 | /* done */ | 
 
 
 
 
 | 570 | cleanup(); | 
 
 
 
 
 | 571 | return 0; | 
 
 
 
 
 | 572 | } |